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Simulation of JC model in Linear Optics(2)

时间:2020-04-25 14:42来源:英语论文
n 12 E gngn n 12 E = 0. (12)That is to say, (n 12 E)2= (gn)2. So, we obtain E1 = n 12 gn andE2 = n 12 + gn. Be taking the result back to eigenequation, and resulting from thefact that C1 and C2 satisf

nω − 12ω − E g√ng√n nω − 12ω − E = 0. (12)That is to say, (nω − 12ω − E)2= (g√n)2. So, we obtain E1 = nω − 12ω − g√n andE2 = nω − 12ω + g√n. Be taking the result back to eigenequation, and resulting from thefact that C1 and C2 satisfy the normalization condition, it can be written as[sinθ cosθ]T.Therefore, we have

 

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